A load 6 kN is to be raised with the help of steel wire find the minimum diameter of steel wire if dress is not exceed 110 N/mm
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Answer:
D = 34.74 × 10⁻³ m
Explanation:
Given,
- Load = 6 KN = 6000 N
- Stress = 110 N/mm = 110 × 10⁶ Pa
THE FORMULA TO CALCULATE THE FORCE,
Force = Stress × Area
Area = Force/Pressure
→ πr² = 6000/110 × 10⁶
→ 3.14 × r² = 54.545 × 10⁻⁶
→ r = (54.545 × 10⁻⁶)/3.14
→ r = 17.371 × 10⁻³ m
∴ D = 2r = 2(17.371 × 10⁻³)
⇒ D = 34.74 × 10⁻³ m
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