A load of 1000 N can be lifted by applying an effort of 250 N. If the load arm is 25 cm, calculate the effort arm. Please show me step wise step. I will mark you as the brainliest.
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Explanation:Solution :
Since the fulcrum lies in between the load and effort, it is class I lever.
Mechanical advantage (M.A.) of levers is given by,
M.A.=effort armload arm=50cm10cm
Thus, mechanical advantage , M.A. = 5.
Given, effort (E)=10N, Load(L)=?
∴L=E×M.A.
=10×5=50N
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