Question

A load of 120 N is kept at a distance of 1.5 m from the fulcrum of a lever.At what distance
an effort of 40 N need to be applied to balance the lever?​

Answer 1

Answer:

Explanation:

load arm × load = effort arm×effort

 

1.5 × 120 = effort arm × 40

 

effort arm = (1.5×120)/40 = 4.5 m

Answer 2

Let the distance be x

120X1.5=40X x

x=1.5X120/40

x=180/40

x=4.5m