Question

a load of 120N is raised by means of a certain weight lifting machine through a distance of 200mm .if the effort applied is 20N and has moved through a distance of 1.5m, find the efficiency of the machine​

Answer 1

Answer:

80,0.5 is the answer mark

Answer 2

Given:

Load = 120N

Distance travelled by load = 200mm

Effort = 20N

Distance travelled by effort = 1.5m

To find:

Efficiency of machine

Solution:

firstly, find the velocity ratio, formula used is -

  $V R = \frac{E_d}{L_d}$

here, $E_d$ = distance travelled by effort (1.5m)

         $L_d$ = distance travelled by load (0.2m)

so, putting all the values we get,

      $V R =\frac{1.5}{0.2}$

     V R = 7.5

and to find mechanical advantage, formula used is-

 $M A = \frac{load_d}{effort_d}$

here, $load_d$ = 120N

         $effort_d$ = 20N

 $M A = \frac{120}{20}$

M A = 6

Now, the efficiency can be calculated as,

   efficiency  $= \frac{M A }{V R} \times 100$

                    = $\frac{6}{7.5} \times 100$

                    = 80%

Therefore, efficiency of the machine will be 80%.