Question

a load of 1250N is lifted by a single movable pulley with an effort of 1000N . Calculate the efficiency

Answer 1

Answer:

I don't know

Explanation:

so...

difficult

Answer 2

Answer:

Formula or i(n this case) relation :

Mechanical advantage = Velocity ratio × Efficiency

Explanation:

Mechanical advantage = Load / Effort

= 1250 / 1000

= 1.25

so, now we got M.A.

next we need to find V.R

V.R of a single movable pulley is always 2.

so, V.R = 2

Applying the values in

Mechanical advantage = Velocity ratio × Efficiency

1.25 = 2 × efficiency

efficiency = 1.25 / 2

= 0.625

efficiency is give in % so, 0.625 × 100

Therefore

Efficiency = 62.5 %.

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