A load of 1kN acts on a bar having cross sectional area 0.8cm ^2 and length 10cm . the stress developed in the bar is?
Answers
Answered by
11
Given: Load = 1 kN, area = 0.8 cm², length = 10 cm.
To find: The stress developed in the bar?
Solution:
- As we have given that the force is acting on the cross- sectional area, so we do not require the length of the bar, which is already given.
- Now, we know the formula of stress, which is :
Stress = Force / Area
- Putting the values in the formula we get:
Stress = 1 kN / 0.8 cm²
- Converting all values to standard form, we get:
Stress = 1000 N / 80 mm²
Stress = 12.5 N / mm²
Answer:
So, the stress developed in the bar is 12.5 N / mm².
Similar questions