Question

A load of 1kN acts on a bar having cross sectional area 0.8cm ^2 and length 10cm . the stress developed in the bar is?​

Answer 1

Given: Load = 1 kN,  area = 0.8 cm²,  length = 10 cm.

To find: The stress developed in the bar?

Solution:

• As we have given that the force is acting on the cross- sectional area, so we do not require the length of the bar, which is already given.

• Now, we know the formula of stress, which is :

                Stress = Force / Area

• Putting the values in the formula we get:

                Stress = 1 kN / 0.8 cm²

• Converting all values to standard form, we get:

                Stress = 1000 N / 80 mm²

               Stress = 12.5 N / mm²

Answer:

            So, the stress developed in the bar is 12.5 N / mm².