Physics, asked by shreeya13, 11 months ago

a load of 25 kg is attached to a diameter of 0.4 cm and length of 100 cm of wire is found to elongate to 102 cm. Find young modulus for the material of the wire.
( reply with solution)

Answers

Answered by Anonymous
22

Explanation:

Stress=F/A=mg/πr²

=250(6.28*10³)

=157*10³

Strain=2/100=0.02

Young's modulus= 157*10³/0.02

=7.85 N/m²

cute dp. love it.....

Answered by rajraaz85
0

Answer:

Modulus of Elasticity, E = 995.22 kg/cm^2.

We know that,

Change in Length = PL/AE

Where,

P = Load

L= Length

A= cross section area

E= Modulus of Elasticity

If we put all the values given in question in formula we can easily get Modulus of Elasticity

Change in Length= PL/AE

2 = (25x100)/((π÷4)x 0.4^2)x E

E = 2500/(0.1256x20)

E = 995.22 kg/cm^2

#SPJ3

Similar questions