a load of 25 kg is attached to a diameter of 0.4 cm and length of 100 cm of wire is found to elongate to 102 cm. Find young modulus for the material of the wire.
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Answers
Answered by
22
Explanation:
Stress=F/A=mg/πr²
=250(6.28*10³)
=157*10³
Strain=2/100=0.02
Young's modulus= 157*10³/0.02
=7.85 N/m²
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Answered by
0
Answer:
Modulus of Elasticity, E = 995.22 kg/cm^2.
We know that,
Change in Length = PL/AE
Where,
P = Load
L= Length
A= cross section area
E= Modulus of Elasticity
If we put all the values given in question in formula we can easily get Modulus of Elasticity
Change in Length= PL/AE
2 = (25x100)/((π÷4)x 0.4^2)x E
E = 2500/(0.1256x20)
E = 995.22 kg/cm^2
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