Question

A load of 4.0 kg is suspended from a ceiling through the steel wire of length 20 m and radius of 2.0

mm. It is found that the length of wire increases by 0.031 mm. Find the young modulus for steel

(Consider g= 3.1π) ​

Answer 1

Answer:

Solution

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Correct option is A)

For equilibrium

Weight = Tension

mg=T

∴T=4×3.1π=12.4πN (as can be inferred from the question)

Y=

△l/l

T/A

=

1000

0.031

/20

12.4π/π(

1000

2

)

2

=

4×0.031

12.4×20×1000×(1000)

2

=2×10

12

N/m

2

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