Question

A load of 400N is lifted up by an effort of 100N . if load distance is 20cm, what will be the effort distance ?

Answer 1

Answer:

Load X Distance from fulcrum = Effort X Distance from fulcrum

400 * 20 = 100 * x

8000/ 100 = x

80 cm = x

Answer 2

Answer:

The effort distance is 80cm

Explanation:

Given that,A load of 400N is lifted up by an effort of 100N.If load distance is 20cm,we are required to find out the effort distance.To solve this problem,we shall use the relation of Mechanical advantage.

It is defined as the ratio of load to effort (or) the ratio of Effort distance to the Load distance.Hence,Mathematically we write it as

$M.A=\frac{Load}{Effort} =\frac{d_{e}}{d_{l}}$

The value of mechanical advantage of the given question is

$M.A=\frac{400N}{100N} =4$

Equating this value with the load and effort distance relation,we get

$4=\frac{d_{e}}{20} = > d_{e}=80cm$

Therefore,the effort distance is found to be 80cm

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