Question

a load of 5 kg is produces an extension of 1mm in a wire which is 1m long and 2mm in diameter . calculate youngs modulus of the wire

Answer 1

Answer:

I hope it is helpful for you

Answer 2

Answer:

A load of 5 kg produces an extension of 1mm in a wire which is 1m long and 2mm in diameter. calculate youngs modulus of the wire will be $7.8025\times10^{9} \ N/m^{2}$

Explanation:

We have the expression for Youg's modulus(Y) as,

$Y=\frac{F L}{A l}$

Where

F - The stretching force or tension on the wire.

L -  Initial length of the wire

A - Area

 l -  Extended length

Given,

Load (m) = 5 kg

        g     = 9.8 $m/s^{2}$

F=  ma  = 5 $\times$ 9.8 = 49 N

L = 1 m

Diameter (d)  = 2 mm = 2 $\times 10^{-3} m$

Radius (r)  = $\frac{d}{2} = 1\times 10^{-3} m$

Thus,   A = $\pi r^{2} = 3.14\times( 1\times10^{-3})^{2} = 3.14 \times 10^{-6} m^{2}$

Substituting the values into the equation(1),

Now,

Equation (1) becomes,

$Y=\frac{49\times 1}{3.14\times10^{-6}\times2\times10^{-3} }$

  = $7.8025\times10^{9} \ N/m^{2}$

Ans :

Extended length = $7.8025\times10^{9} \ N/m^{2}$