Question

A load of 500 N is lifted by applying an effort of 200 N with the help of a lever. The effort distance and load distance are 60 cm and 20 cm respectively, the value of MA and VR respectively are: *​

Answer 1

Explanation:

Solution

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Given,

Mechanical advantage =

input force

output force

=1.6

input load=

1.6

Output load

=

1.6

500

=312.5 N

Effort of 312.5N is required

Answer 2

Answer:

A load of 500 N is lifted by applying an effort of 200 N with the help of a lever. The effort distance and load distances are 60 cm and 20 cm respectively.

1. Mechanical advantage = $2.5$
2. Velocity ratio     = $3$

Explanation:

• Let L be the load, E be the effort, $L_d$ be the load distance and $E_d$ be the effort distance of a lever. Then, Mechanical advantage and velocity ratio can be defined as,

• $\text{ { Mechanical\ advantage }(M . A)}=\frac{\text { Load }}{\text { Effort }} = \frac{L}{E}$    ...(1)

• $\text { Velocity ratio }(\text { V.R })=\frac{E_{d}}{L_{d}}$         ...(2)

In the question, it is given that,

$L = 500\ N$                               $E = 200\ N$

$E_d = 60\ cm= 0.60\ m$               $L_d = 20\ cm = 0.20\ m$

M.A can be obtained by substituting these values into equation (1)

$\text M \cdot \text A=\frac{500}{200}=2.5$

V.R  can be obtained by substituting the values of $E_d$ and $L_d$ into equation (2)

$\text V \cdot \text R =\frac{0.60}{0.20}=3$