Question

A load of 500N is lifted up by an effort of 200N. If the load distance is 20cm, what will be the effort distance? (Ans : 50cm)

Answer 1

Answer:

effort arm = 50cm

Explanation:

Load × load arm = effort × effort arm

500N × 20cm = 200N × effort arm

1000Ncm = 200N × effort arm

50cm = effort arm

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Answer 2

Answer:

A load of 500N is lifted up by an effort of 200N. If the load distance is 20cm, the effort distance will be $50cm$

Explanation:

• According to the principle of levers,

        Load $\times$ Load distance  =Effort

• If L is the load and E is the effort. The distance between the load and fulcrum be the load distance$L_d$ and the distance between effort and fulcrum be the Effort distance$E_d$.

        So,

         $L\times L_d = E\times E_d$    ...(1)

In the question, it is given that,

$L = 500\ N$                   $E = 200\ N$

$L_d = 20\ c m$                 $E_d = ?$

Using equation (1),

$E_d = \frac{L\times L_d}{E}$

Substitute the values into the above equation.

$E_d = \frac{500\times 20}{200} = 50\ cm$

Effort distance is $50cm$