Question

a load of 800n is lifted by an effort of 200n. If the load is placed at a distance of 10cm from the fulcrum,what will be the effort distance​

Answer 1

Answer:

=90.6%

Explanation:

Load (l) = 680N

Effort (E) = 500N

Length of slope (l) = 12m

Height of slope (h) = 8 m

Now,

Output work = load * height

680 *8 = 5.44 *103 J

Input work = effort * length = 500 *12 = 6000J

Mechanical advantage (M.A) = loadeffort= 600500=1.36

Velocity ratio (V.R) =lh=128 = 1.5

Efficiency =M.A100%V.R= 90.6%