Question

a load of 80kn is jointly supported by theee rods of 20 mm diameter the rod are adjusted in such a way that they share the liad equal if an additional load of 50 kn is added find the final stress in steel and copper take E for copper as 100gpa and for steel as 200gpa​

Answer 1

Answer:

The final stress in the copper rods is 0.4136 kN/mm^2.

Step-by-step explanation:

• Prior to adding the additional load, we must first ascertain the initial stress in the rods. 
• Each rod will be bearing a load of 80/3 = 80/3=26.67>>26.67 kN
• since the three rods are supporting a load of 80 kN and have equal diameters.

        The formula A = *(d/2)2 

•  The cross-sectional area of a rod with a 20 mm diameter is 

        3.1416 * (20/2)2 = 314.16 mm2.

• The stress in the steel and copper rods will rise when the additional 50 kN load is introduced. 
• The formula = F/A, where F is the total load sustained by the rod (80 + 50 = 130 kN) and A is the rod's cross-sectional area (314.16 mm2), can be used to determine the final stress in steel rods. 
• The steel rods' final stress is equal to 130 kN / 314.16 mm2 = 0.4136 kN/mm2.

So, the final stress in the copper rods is 0.4136 kN/mm^2.

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