Question

A load of mass 30 kg is lifted up by 7.0 m. Calculate the work done. (Take 8 9.8 ms.) ​

Answer 1

Answer:

work done = mgs

= 30*7*9.8

=2958joule

Answer 2

${ \text{ \red{ \underline{ \purple{ \underline{Given data}}}}}:-}$

◐ Mass ( m ) of load = 30 kg.

◐ Load lifted at height = 7.0 m

${ \text{ \red{ \underline{ \purple{ \underline{Solution}}}}}:-}$

Load displace ( s ) at height 7.0 m,in upward direction. {displacement ( s ) = 7.0 m }

We know, there is need of force to lift load.

Hence,

→ Force = mass × acceleration

{Here acceleration is acceleration due to gravity 'g' = 9.8 m/s², because load is lifted in upward direction }

→ Force = 30 × 9.8

→ Force = 294 N

Now, by formula of work done

→ Work done = force × displacement

→ Work done = 294 × 7.0

→ Work done = 2058 Joule

Hence, work done is 2058 Joule.