Question

A load weighing 20,000N is placed on a side with area 0.1 m² , then the pressure exerted on the ground is

Answer 1

Given

• Force = 20000 N
• Area = 0.1 m²

To Find

• Pressure Applied

Solution

☯ Pressure = Force/Area

• So here the force is the weight of the body

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✭ According to the Question :

➞ Pressure = Force/Area

• Force = 20000 N
• Area = 0.1 m²

➞ Pressure = 20000/0.1

➞ Pressure = (20000 × 10)/(0.1 × 10)

➞ Pressure = 200000/1

➞ Pressure = 200000 Pa

∴ Pressure Applied is equal to 200000 Pa

Answer 2

Given :-

Force applied = 20000 N

Area = 0.1 m²

To Find :-

The pressure exerted on the ground.

Analysis :-

Here we are given with the force and the area.

In order to find the pressure exerted substitute the values given in the question such that pressure is equal to force divided by area and find the pressure exerted on the ground accordingly.

Solution :-

We know that,

• f = Force
• p = Pressure
• a = Area

Using the formula,

$\underline{\boxed{\sf Pressure=\dfrac{Force}{Area} }}$

Given that,

Force (f) = 20000 N

Area (a) = 0.1 m²

Substituting their values,

⇒ p = f/a

⇒ p = 20000/0.1

⇒ p = 200000 N/m²

Therefore, the pressure exerted on the ground is 200000 N/m².