Question

A loaded coin is thrown three times in succession. The probability that you will head on any pitch is of ¼. Find the probability that:
Exactly two tails appear
Two or three tails appear

Answer 1

Answer:

i think it will help you

Step-by-step explanation:

fair coin has the probability of heads equal to the probability of tails, so P(tail) = P(head) = 1/2. We are told that the coins is unfair so P(tail) ≠ P(head).

The probability that the coin displays heads after it’s flipped is three times the probability that it will display tails: P(h) = 3*P(t). Sin, the sum of these probabilities must be 1, then P(h) + P(t) = 1:

3*P(t) + P(t) = 1;

P(t) = 1/4 and P(h) = 3/4.

The question ask to find the probability that, after 5 coin flips, the coin will have displayed heads exactly 3 times. Exactly 3 heads can occur in several different ways:

HHHTT

HHTHT

HTHHT

THHHT

THHTH

THTHH

TTHHH

HHTTH

HTTHH

HTHTH

Basically, this is permutations of 5 letters HHHTT, out of which 3 H's and 2 T's are identical: 5!/(3!2!) = 10.

Now, each of the above 10 cases have the probability of (3/4)^3*(1/4)^2. Thus, the overall probability of P(HHHTT) is .

Answer 2

Answer:

I'm really sorry

to you

because I can't answering that

sorry po