Question

A loan was taken on compound interest at a rate of 10 pcpa it was settled after 3 years by paying rs 26620 how many rupees of loan was taken

Answer 1

Step-by-step explanation:

we know that,

A=p{1+R÷100}n

26620=p{1+10÷100}3

26620=p{110÷100}3

26620×{100÷110}3=p

35,431.22=p

Answer 2

Rs. 20000 was taken as loan.

Step-by-step explanation:

Since we have given that

Amount = Rs. 26620

Rate of interest = 10 pcpa

Number of years = 3

So, it becomes,

$A=P(1+\dfrac{r}{100})^n\\\\26620=P(1+0.1)^3\\\\26620=P(1.1)^3\\\\\dfrac{26620}{1.1^3}=P\\\\P=20000$

Hence, Rs. 20000 was taken as loan.

# Learn more:

A loan was taken on compound interest at rate of 10p.c.p.a .It was settled after 3 years by paying rupees 26,620 .How many rupees of loan was taken ?​

https://brainly.in/question/9107083