Math, asked by munesharya67, 4 days ago

A lock in a canal is 40m long , 7m wide. When the sluices are opened, the depth of water in the lock decreases from 5m to 3m 80cm. How many metres of water runs out ?

Answers

Answered by nihalrehan26
0

length =40m

breadth=7m

height=5m

volume =l×b×h

volume of lock when level of the water decreases 5m to 3m

=80=3.8,m=40×7×3.8=1064m3

=1400-1064m3=336m3

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Answered by atharvpathare8
1

Step-by-step explanation:

length of lock = 40m

Breadth of lock = 7m

Height of water in lock, h = 5m

So Nolame = lxbxh •=(40x7x5) m = 1400m³

Volume of lock when level of water decrease from 5m to 3m80cm = (3.8m)

= (40x7x3-8) m

-T064m²

1064o, water runs out from lock = (1400-1064) m³ 3 = 3.36m³ (Ansmlength of lock = 40m

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