Question

A locomotive exerts a force of 7500N and pulls a train by 1.5km .the work done by the locomotive in mega joule is?

Answer 1

Hey here is your answer
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Force = 7500N
Displacement = 1.5 km = 1.5 × 1000 m

Work done = force × displacement
= 7500 × 1.5 × 1000 joule
= 7500 × 1500 joule
= 11250000 joule
= 11.25 Mega jould
----- (as 1 Mega joule = 10^6 joule)
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Answer 2

Answer:

1.125 × 10⁻⁵ mega joule

Explanation:

Force exerted by a locomotive, F = 7500 N

Displacement caused y pulling, $d=1.5 km= 1.5\times 10^{-3}\ m$

Work done is given by :

W = F × d

$W=7500\times 1.5\times 10^{-3}$

W = 11.25 Joules

$W=1.125\times 10^{-5}\ MJ$

Hence, the work done by the locomotive is 1.125 × 10⁻⁵ mega joule.