Physics, asked by jerinjs8978, 9 months ago

A long cylinder carries a charge density that is proportional to the distance from the axis r = ks, for some constant k. Find the electric field inside this cylinder.

Answers

Answered by sanjeevk28012
6

Answer:

The Electric field inside cylinder is \dfrac{1}{3} k s²    in s^ direction .

Explanation:

Given as :

For a long cylinder

The distance from axis = s

The charge density proportional to distance

i.e  r = k s

where k is constant

Let the electric field inside cylinder = E

According to question

From the Gaussian theorem

Total charge enclosed = Q_i_n = l \int_{0}^{s}(ks')s'ds'd\phi

Or,   Q_i_n = l k \int_{0}^{s}(ks'^{2})ds'd\phi

Or, Q_i_n = l k \dfrac{2}{3} π s²

i.e Q_i_n =  \dfrac{2}{3} k π s² l

So, The charge enclosed inside cylinder =   Q_i_n =  \dfrac{2}{3} k π s² l   column

Again

Electric field inside cylinder = \dfrac{Q_in}{\varepsilon _02\Pi sl}

i.e E = \dfrac{\frac{2}{3}k\Pi ls^{3}}{\varepsilon _02\Pi sl}

  E = \dfrac{1}{3} k s²    in s^ direction

So, The Electric field inside cylinder =   E = \dfrac{1}{3} k s²    in s^ direction

Hence , The Electric field inside cylinder is \dfrac{1}{3} k s²    in s^ direction . Answer

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