Physics, asked by dhimanyogesh1186, 11 months ago

A long cylindrical vessel is half filled with a liquid. When the vessel is rotated about its own vertical
axis, the liquid rises up near the wall. If the radius of vessel is 5 cm and its rotational speed is 2 rotations
per second, then the difference in the heights between the centre and the sides, in cm. will be
TAIEEE-201​

Answers

Answered by aristocles
5

Answer:

The difference in the heights between the centre and the sides is 2 cm

Explanation:

As we know that if cylinder is rotated about its axis then we can take reference at the vertex of the shape of the free surface of liquid

So here we will have

y = \frac{\omega^2 x^2}{2g}

here we can say

\omega = 2\pi f

f = 2 rotations per second

\omega = 2\pi(2) = 4\pi rad/s

x = 5 cm

now we have

y = \frac{(4\pi)^2(0.05)^2}{2(9.81)}

y = 2 cm

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Topic : Fluids

https://brainly.in/question/5125324

Answered by Allen987
2

here is the answer for you dear

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