A long plank of mass m is intially at rest on a frictionless surface .A small block with mass m(m=alpham) anf intial speed u0nsludes on the top of the larger plank. The coefficient of friction between the block and plank is u
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Answer:
The answer will be - umgL
Explanation:
According to the problem it is given that the mass of the plank is m and the mas of the block is alpham , the initial speed of the block is u0
Now let the friction force needed to move for the block is f
let the displacement is L
Now as f is constant therefore the workdone ,dw = f.ds => dw = f ds cos180
dw = - fds
Now by integrating
w = -f L
= -umgL
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