Science, asked by mohdatifraza, 9 months ago

A long shunt compound generator deliver to
load current of 50 Amp and soo volt and
The resistance of Armature series field and
shant field are 0.05 and 0.032 8 2500
respectevily, Calculate the generated em f'and
armature current and brush drop is lv borush​

Answers

Answered by deepnkumarshah
1

Answer:

long shunt compound generator deliver to

load current of so Amp and 500 volt and

The resistance of Armature series field and

shant field are 0.05 and 0.03 & 2500

respectevily, Calculate the generated em frand

armature current and brush drop is 1v/brush

Answered by Fatimakincsem
0

Thus the value of emf  E ≈ 225 V

Explanation:

  • il = 30 A
  • E = required emf induced

The brush contact drop must be 1.10 V instead of 110 V because brush consume negligible amount of electricity.

Assuming contact drop is given for a single brush.

So contact drop = 1.10 V for one brush

For two brushes = 2×1.10 = 2.20 V

Applying KVL to three meshes

(il + is)0.05 + 0.03il + ilR + 2.20 = E

ilR = 220

0.05 is + 0.08×30 + 222.2 = E ------(1)

200 is – Ril – 0.03 il  = 0

=> 200 is – 220 – 0.03×30  = 0  -----(2)

(il + is)0.05 + 200 is + 2.20 = E

200.05 is + 0.05×30+ 2.20 = E ------(3)

Solving the equations we have  

E = 224.65 V

E ≈ 225 V

Thus the value of emf  E ≈ 225 V

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