A long shunt compound generator deliver to
load current of 50 Amp and soo volt and
The resistance of Armature series field and
shant field are 0.05 and 0.032 8 2500
respectevily, Calculate the generated em f'and
armature current and brush drop is lv borush
Answers
Answer:
long shunt compound generator deliver to
load current of so Amp and 500 volt and
The resistance of Armature series field and
shant field are 0.05 and 0.03 & 2500
respectevily, Calculate the generated em frand
armature current and brush drop is 1v/brush
Thus the value of emf E ≈ 225 V
Explanation:
- il = 30 A
- E = required emf induced
The brush contact drop must be 1.10 V instead of 110 V because brush consume negligible amount of electricity.
Assuming contact drop is given for a single brush.
So contact drop = 1.10 V for one brush
For two brushes = 2×1.10 = 2.20 V
Applying KVL to three meshes
(il + is)0.05 + 0.03il + ilR + 2.20 = E
ilR = 220
0.05 is + 0.08×30 + 222.2 = E ------(1)
200 is – Ril – 0.03 il = 0
=> 200 is – 220 – 0.03×30 = 0 -----(2)
(il + is)0.05 + 200 is + 2.20 = E
200.05 is + 0.05×30+ 2.20 = E ------(3)
Solving the equations we have
E = 224.65 V
E ≈ 225 V
Thus the value of emf E ≈ 225 V