Question

A long solenoid has 800 turns per metre length of solenoid. A current of 1.6 a flows through it. The magnetic induction at the end of the solenoid on its axis is

Answer 1

B=(µ0 ni(cosθ2-cosθ1))/2.Since you have asked to calculate induction at one end along the axis, θ2=90

and θ1=0.

Answer 2

Answer:

The magnetic induction at the end of the solenoid on its axis is $8.04\times10^{-4}\ T$.

Explanation:

Given that,

Number of turns = 800

Current = 1.6 A

We need to calculate the magnetic induction

Using formula of magnetic induction

$B=\dfrac{\mu_{0}nI}{2}$

Where,

n = number of turns per meter length

I = current

Put the value into the formula

$B=\dfrac{4\pi\times10^{-7}\times800\times1.6}{2}$

$B=8.04\times10^{-4}\ T$

Hence, The magnetic induction at the end of the solenoid on its axis is $8.04\times10^{-4}\ T$.