Question

A long solenoid is wound with 100
turns/m and current is increasing at 250
A/s, the cross section of the coil has
area 2 cm2. Find the induced electric
field within the loop of radius 1 cm.
(Take magnetic permeability = 410 x 10
T-mal)​

Answer 1

Answer:

Explanation:

The emf is given by the formula:

e = -μ₀nA × dI/dt

Where,

μ₀ = 4π × 10⁷ H/m

n = 100 turns/m

A = 2 cm

dI/dt = 250 A/s

On substituting the values, we get,

e = 4π × 10⁷ × 100 × 2 × 10⁻² × 250

∴ e = 6.28 × 10¹⁰ V

Now, the induced electric field is given by the formula:

E = e/(2πr)

Where,

r = Radius of loop = 0.01 m

On substituting the values, we get,

E = (6.28 × 10¹⁰)/(2π × 0.01)

∴ E = 1 × 10¹² V