Physics, asked by Kiran78301, 7 months ago

A long solenoid of cross-sectional radius a = 10 cm has a thin insulated wire ring tightly put on its winding One half of the ring hasthe resistance 77-times that of the other half. The magnetic induction produced by the solenoid varies with time as B = bt whereb = 4 T/s (constant). Now the magnitude value of electric filed strength in the ring is found to bel0 x 10-2 N/C Find the valueofη.​

Answers

Answered by swastikameena5a
2

Answer:

I don't this questions answer but can you help me

Answered by abdulraziq1534
0

Concept Introduction:-

It might resemble a word or a number representation of the quantity's arithmetic value.

Given Information:-

We have been given that a long solenoid of cross-sectional radius a = 10cm has a thin insulated wire ring tightly put on its winding one half of the ring has the resistance 77-times that of the other half.

To Find:-

We have to find that the value of η.​

Solution:-

According to the problem

$\frac{\xi}{2}-\pi a E=r I$ and, $\frac{\xi}{2}+\pi a E=\eta r I$, where $\xi$ is the total induced e.m.f. From this, $\xi=(\eta+1) r I$

and $E=\frac{1}{2 \pi a}(\eta-1) r I=\frac{1}{2 \pi a} \frac{\eta-1}{\eta+1} \xi$

But by Faraday's law, $\xi=\pi a^{2} b$ so, $E=\frac{1}{2} a b \frac{\eta-1}{\eta+1}$

Final Answer:-

The correct answer is $E=\frac{1}{2} a b \frac{\eta-1}{\eta+1}$.

#SPJ3

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