Question

a long spring is streached by 2cm and its potential energy is e. if the spring is streached by 4 cm

Answer 1

$potential \: energy \: of \: a \: spring \: is$
$PE = \frac{1}{2} k {x}^{2}$

$when \: \: x = 2cm$
$PE = e = \frac{1}{2} k {x}^{2} = \frac{1}{2} k \times {2}^{2} = 2k$

$if \: \: x = 4cm$
$PE = \frac{1}{2} k \times {4}^{2} = 8k = 4e$

Thus, if spring is stretched by 4cm, the potential energy will be 4e.

Answer 2

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$potential \: energy \: of \: a \: spring \: is$

$PE = \frac{1}{2} k {x}^{2}$

$when \: \: x = 2cm$

$PE = e = \frac{1}{2} k {x}^{2} = \frac{1}{2} k \times {2}^{2} = 2k$

$if \: \: x = 4cm$

$PE = \frac{1}{2} k \times {4}^{2} = 8k = 4e$

Thus, if spring is stretched by 4cm, the potential energy will be 4e.

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