Question

A long spring is stretched by 2 cm. Its potential energy is
U. If the spring is stretched by 10 cm, its potential energy
would be
U
(a) U/25
(b) U/5
(c) 5U
(d) 25U​

Answer 1

$\huge \purple A \purple N \purple s \purple W \purple e \purple \R :-$

• refer attachment pls .......

Answer 2

Solution:

As per the given data,

• x₁ = 2 cm
• x₂ = 10 cm

The potential energy of the spring is given by,

$\blacksquare \:$ U = ½ kx²

here,

• U = potential energy
• k = spring constant
• x = elongation of the spring

From this, we can conclude that,

• U ∝ x²

Hence,

⇒ U / U' = x₁² / x₂²

⇒ U / U' = 4 / 100

⇒ U / U' = 1 / 25

⇒ U' = 25 U

The new potential energy is 25U.