a long spring is stretched by 2cm in potantial energy is V what will be the its potantial energy if the spring is stretched by 10cm solution
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Here's your answer
We know, potential energy of spring is given by (1/2)kx² where k is spring constant and x is stretched distance.
Here , x=2cm so, U=(1/2)k*2²=2k
For, x=10cm :-
E=(1/2)k*10²=50k=25(2k)=25U.
Final potential energy will be 25U.
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Here's your answer
We know, potential energy of spring is given by (1/2)kx² where k is spring constant and x is stretched distance.
Here , x=2cm so, U=(1/2)k*2²=2k
For, x=10cm :-
E=(1/2)k*10²=50k=25(2k)=25U.
Final potential energy will be 25U.
I think this will help you
pls mark me as the brainliest
bye, thanks and have a great day ahead
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