a long Steel bar under a tensile stress due to a force f as shown for what angle theta the tensile and shearing stress are maximum
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According Problem F is applied along horizontal so resolving into two component one is parallel to inclined one and other is perpendicular to inclined me
F parallel =F11=Fcosθ
F perpendicular =F⊥=Fsinθ
F⊥ Producer tensile stren , F11 producer shear stren
Area of focus aa1 then sinθ=A1A⇒A1=A/sinθ
Tensile stren on the plane aa1
aa1=A1F⊥⇒A/sinθFsinθ=AFsin2θ
Shearing stren on the plane aa1
Shearing stren =areaParallel force
=A1f11=A/sinθFcosθ=AFsinθcosθ
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