Physics, asked by rijeeshvaliyil4212, 9 months ago

A long straight conductor carrying a current lies
along the axis of a ring. The conductor will exert a
force on the ring if the ring
(a) carries a current
(b) has uniformly distributed charge
(c) has non-uniformly distributed charge
(d) none of the above

Answers

Answered by ItsShreedhar
1

\rule{200}{2}

\huge\boxed{\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R:-}}}}}

a) carries a current

In a way we can assume that current carrying ring will act as a dipole placed perpendicular to the magnetic field due to straight conductor hence it will experience torque. Since field will be uniform at symmetrical points on the axis of symmetry as the axis of ring. Therefore, no force will act on the ring

Answered by Anonymous
1

Answer:

a) carries a current

In a way we can assume that current carrying ring will act as a dipole placed perpendicular to the magnetic field due to straight conductor hence it will experience torque. Since field will be uniform at symmetrical points on the axis of symmetry as the axis of ring. Therefore, no force will act on the ring

Explanation:

hope it will be help you. .....

Similar questions