Question

A long straight solid conductor of radius 5 cm carries a current of 3 ampere which is uniformly distributed over its circular cross-section find the magnetic field induction at a distance 4 cm from the axis of the conductor ,Given relative permeability of the conductor 1000

Answer 1

Answer:

Explanation:

It is given here,

I = 3A

Distance of point, r = 4cm = 4 * 10⁻² m

Radius of conductor, a = 5 cm = 5 * 10⁻² m

=> The magnetic field at a point inside the conductor carrying a current I uniformly distributed is :

B = μ₀Ir / 2πa²

= 4π * 10⁻⁷ * 3 * 4 * 10⁻² / 2 * π * (5 * 10⁻²)²

= 24 * 10⁻⁹ /  25 * 10⁻⁴

= 9.6 * 10⁻⁶ T

Answer 2

Answer:

The magnetic field is 0.96×10⁻⁵ T

Explanation:

Radius r = 5cm

Current I = 3A

Distance d = 4cm

Now, the magnetic field at a point inside the conductor

B = μ₀Id / 2πr²

B = 4π×10⁻⁷×3×4×10⁻² /   2π×25×10⁻⁴

B = 0.96×10⁻⁵

B = 0.96×10⁻⁵ T

Hence, the magnetic field is 0.96×10⁻⁵ T