Question

a long straight thin conductor carries a current of 40A in south to North direction what is the magnetic field at a point 2.0m west of the wire. With explanation ​

Answer 1

Answer:

hope it helps

Explanation:

I=40A

r=15cm=15×10

−2

m

∴ B =

2πR

μ

0

I

=

15×10

−2

2×10

−7

×40

=

15

80

×10

−5

=5.34×10

−5

T

Answer 2

Answer:

4 × 10^-6 T

Explanation:

Given,

I =40A

r = 2.0m

so, B =μ0I/2πr

B = 2× 10^-7 ×40/2

B = 4× 10^-6 T