Hindi, asked by vishagh, 1 year ago

A long straight wire AB carries a current 4A.A proton travels at 4×10^6m/s parallel to the wire,0.2 from it and in a direction opposite to the current .Find the force which the magnetic field of current exerts on the proton

Answers

Answered by nobita41
6
Dear Student,r=0.2mI=4AThecurrentcarryingwireABProducesamagneticfieldatthepositionofpointP,B=μoI2πr,whichisperpendiculartoplaneofpaperdownward.Theprotonmovesperpendiculartothismagneticfield,Hence,experiencesthemagneticforce,Fm=qvBMagneticfield,B=μoI2πrB=4π×10−7×42π×0.2=4×10−6TMagneticforce,Fm=qvBv=4×106m/sFm=1.6×10−19×4×106×4×10−6Fm=25.6×10−19NAccordingtoflemingslefthandrule,thedirectionofforceisawayfromwireAB.Was this answer hel
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