Question

A long straight wire carries a current of 10 ampere. An electron moving at 10⁷ m/s is 2cm from the wire. Find the force acting on the electron if its velocity is directed towards the wire​

Answer 1

Answer:

Given: Current in wire= 50A

            Speed of electron=107ms−1

Solution: Let us assume the current is directed in +y direction.

As we know, magnetic field due to straight wire is given by,

B=2πrμ0i

=2π×0.054π×10−7×50

=0.0002T

According to question, v and B are perpendicular to each other.

F=qvb

Substituting the values we get,

=1.6×10−19×107×0.0002

=3.2×10−16N

$Given: Current in wire= 50A</p><p></p><p>            Speed of electron=107ms−1</p><p></p><p>Solution: Let us assume the current is directed in +y direction.</p><p></p><p>As we know, magnetic field due to straight wire is given by,</p><p></p><p>B=2πrμ0i</p><p></p><p>=2π×0.054π×10−7×50</p><p></p><p>=0.0002T</p><p></p><p>According to question, v and B are perpendicular to each other.</p><p></p><p>F=qvb</p><p></p><p>Substituting the values we get,</p><p></p><p>=1.6×10−19×107×0.0002</p><p></p><p>=3.2×10−16N</p><p></p><p>$

Answer 2

Answer:

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