Question

a long straight wire carrying a current of 10 ampere and qan electron
travels at a speed of 5 into 10 power 6 metre per second wire at 0.1 away from the force exerted by the magnetic field of the current on the electron​

Answer 1

Current on the wire - i = 5A

Speed of electron v = 5*10³×² m/s

Distance between wire and electron d = 0.1 m

Thus, the magnetic field due to the straight wire at a distance d from wire is

= B= uoi/(2πd) = (4π× 10 power -7)/ (2π×0.1)

= B= 10 power -5 T

Since the electron is moving parallel to the wire so the direction of the magnetic field will be perpendicular to the direction of the electron.

thus the force on electron is = F=gvB= (1.6× 10 power -19) (5×10²×²)(10 power -5)

F= 8 × 10 power -20 N