Physics, asked by Jeswanth9934, 1 year ago

A long straight wire carrying current i is bent at its midpoint to form an angle of 45 degree induction of magnetic feild at point p distant r from point of bending

Answers

Answered by alinakincsem
3

A long straight wire carrying current i is bent at its midpoint to form an angle of 45 degree induction of magnetic field at point p distant r from point of bending is;

μ₀i/4πd[√2−1]

Answered by lidaralbany
2

Answer:The induction of magnetic field at point p is B = \dfrac{\mu_{0}I}{4\pi r}\dfrac{1}{\sqrt(2)}.

Explanation:

Given that,

Angle \theta = 45^{0}

Distance from the bent point to p point = r

We know that,

The induction of magnetic field is

B = \dfrac{\mu_{0}I}{4\pi r}(sin\theta)

B = \dfrac{\mu_{0}I}{4\pi r}(sin\theta)_{0}^{\dfrac{\pi}{4}}

B = \dfrac{\mu I}{4\pi r}(sin0^{0}-sin(\dfrac{\pi}{4}))

B = \dfrac{\mu_{0}I}{4\pi r}(0-\dfrac{1}{\sqrt{2}})

B = \dfrac{\mu_{0}I}{4\pi r}\dfrac{1}{\sqrt{2}}

Hence, The induction of magnetic field at point p is B = \dfrac{\mu_{0}I}{4\pi r}\dfrac{1}{\sqrt{2}}.

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