Question

A long wire having uniform linear charge density is bent in the shape as shown in figure. The electric field at point P is ​

Answer 1

Given:

A long wire having uniform linear charge density is bent in the shape as shown in figure.

To find:

Electric field at point P ?

Calculation:

At point P ,

• The parallel SEMI-INFINITE Wires will exert equal and opposite electrostatic field intensity such that they will cancel each other.

• So, the net field intensity will be contributed only by the semicircular part.

$E_{net}= E_{semi \: circle}$

$\implies E_{net}= \dfrac{ \lambda}{2\pi \epsilon_{0}R}$

So, final answer is :

$\boxed{ \bf E_{net}= \dfrac{ \lambda}{2\pi \epsilon_{0}R} }$