Question

A long wire with a small current element of length 1 cm is placed atthe origin and carries a current of 10A along X-axis. Find out themagnitude and direction of magnetic field due to the element on Y axisat a distance 0.5 m from it.​

Answer 1

The magnetic field on the element is B = 2.8×10^−4π.

Explanation:

Q  1  =Q  2  =45°      (0.5/ 0.5 = tanθ)

B =  M o  /  4πr  l / r (sinϕ  1  +sinϕ  2 )

=  Mo /4π  ×   10/0.5 x 10^-2  × [ sin(45) + sin(45) ]

=  10^7 × x 10 / 10^−2  x 0.5  x √2

B = 2.8×10^−4π

Thus the magnetic field on the element is B = 2.8×10^−4π.

​Also learn more

A metal wire of resistance 5 ohm was connected to a battery of 10 volt. Then the current through the wire and the power spent on the wire are?

https://brainly.in/question/11967249

​