A loop of area 1m^2 is placed in a magnetic field B=2T, such that plane of the loop is parallel to the magnetic field. If the loop is rotated by 180^@, the amount of net charge passing through any point of loop, it its resistanc is 10Omega is
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Answer:
Q = dfie/R
Q = (1× 2× 2)/100
Q = 4×10^-2
hope the answer will help you
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