Question

A loop of mass 2kg and radius 20cm rolls along the ground at the rate of 10 ms –1 . Calculate its kinetic energy.​

Answer 1

Answer:

kinetic energy is 100joules

Explanation:

$k.e = \binom{1}{2} \times mv {}^{2} \\ \binom{1}{2} \times 2 \times {10}^{2} \\ \binom{1}{2} \times 2 \times 100 \\ 100joules$