Question

A loop of radius 1 m is placed on a inclined of 60 degree with the magnetic field of 100 T, corresponding flux will be

Answer 1

Answer:

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Answer 2

Given:

A loop of radius 1 m is placed on a inclined of 60 degree with the magnetic field of 100 T.

To find:

Magnetic flux?

Calculation:

• Angle between area vector and field intensity will be : (90° - 60°) = 30°.

• Let flux be $\phi$.

$\therefore \phi = B \times A \times \cos( \theta)$

$\implies \phi = 100 \times (\pi {r}^{2} ) \times \cos( {30}^{ \circ} )$

$\implies \phi = 100 \times (\pi \times {1}^{2} ) \times \dfrac{ \sqrt{3} }{2}$

$\implies \phi = 50\pi \sqrt{3}$

$\implies \phi = 272.03 \: T {m}^{2}$

So, flux is 272.03 Tm².