A loop of radius 1 m is placed on a inclined of 60 degree with the magnetic field of 100 T, corresponding flux will be-
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A loop of radius 1 m is placed on a inclined of 60 degree with the magnetic field of 100 T, corresponding flux will be-
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Concept:
The quantity of magnetic field lines that travel through a specific closed surface is known as the magnetic flux. It offers a way to measure the total magnetic field that traverses a specific surface area.
A magnetic field: A vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.
Given:
A loop is placed on an incline of 60 degrees with a magnetic field of 100 T. The radius of the loop is 1 m.
Find:
The magnetic flux.
Solution:
The radius of the loop is r = 1 m.
The magnitude of the magnetic field, B = 100 T
The angle between the field intensity and the area vector is:
= (90° - 60°) = 30°
The magnetic flux Φ of the loop will be:
Ф = B × A × cos(θ)
Φ = 100(πr²)(cos(30°))
Ф = (100) × (π(1)²) × (cos(30°)
Ф = 50π(√3)
Ф = 272.03 Tm²
The corresponding flux is 272.03 Tm².
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