A lorry of mass 2000kg is moving with a uniform velocity of 9.8m/s.find the force required to stop the vehicle in 20 seconds
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Answered by
1
it is given that mass is 2000kg, initial velocity is 9.8,time is 20seconds.
acceleration=v-u/t
a=0-9.8/20
=-9.8/20
=-0.49
force=mass×acceleration
force=2000×-0.49
=-980Newton
acceleration=v-u/t
a=0-9.8/20
=-9.8/20
=-0.49
force=mass×acceleration
force=2000×-0.49
=-980Newton
Answered by
1
it is given that m=2000kg and u=9,8 t=20second so a=v-u/t 0-9.8/20=0.49 f=ma 2000*-0.49=-980Newton
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