Question

A lorry tube has a capacity of 200 liters air is
pumped into it by means of a hand pump whose
barrel has a volume of 100cc, the number of
strokes required to inflate the tube to a pressure
of 10 atmosphere is
1.200 2.2000 3. 152000 4.1600​

Answer 1

Answer:

Let us simplify this question by making the following assumptions:

Air is pumped into the tube slowly so that the process is isothermal, i.e., constant temperature.

A positive displacement type of pump which inducts air at atmospheric pressure is used to fill up the tube

Ideal gas law is applicable

Moving on, let’s assign some letters to the parameters that we are going to play with.

vi = initial volume of air in the tube

v = full capacity volume of tube

P = initial pressure of air in the tube

p = final pressure of air in the tube after inflating it

Pa = atmospheric pressure

V = volume of air delivered by the pump in one stroke

r = gas constant for air

mi = initial mass of air inside the tube

mf = final mass of air inside the tube

d = density of air at ambient conditions

T = ambient temperature in kelvin

Applying the ideal gas law to deflated tube,

P × vi = mi × r × T

mi = (P×vi)/(r×T)

Now, apply the same law to inflated tube

p × v = mf × r × T

mf = (p×v)/(r×T)

The net mass of air entering the tube is mf - mi

mf - mi = [(p×v)-(P×vi)]/(r×T)

This difference in mass was pumped into the tube with ’n’ strokes.

So,

n×V×d = [(p×v)-(P×vi)]/(r×T)

Now, the density of air is given by

d = Pa / (r×T)

Substituting for ‘d’ in the equation and simplifying,

n = [(p×v)-(P×vi)] / (V × Pa)

Hope that helps

Explanation:There u go.

Answer 2

Answer:

Explanation:

Air is pumped into the tube slowly so that the process is isothermal, i.e., constant temperature. 2. A positive displacement type of pump which inducts air at atmospheric pressu. ... pump whose volume is V. The number of strokes required to inflate the tube ... p = final pressure of air in the tube after inflating it.

1 answer

hope it helped

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