Question

A lot consists of 10 good articles 4 with minor defects 2 with major defects

Answer 1

Answer:

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Given that,

Total number of articles n = 10

No of articles with minor defects = 4

Probability of articles with minor defects Px = number of articles with minor defect ÷ total number of articles

Px = 4÷10 = 0.4

No of articles with major defects = 2

Probability of articles with minor defects Py = number of articles with minor defect ÷ total number of articles

Py = 2÷10 = 0.2

On random selection of 1 article probability that there is no defect means there in no minor defect or no major defect is give by

P = 1 - (Px + Py) = 1 - Px - Py

P = 1 - 0.4 - 0.2 = 0.4

P = 0.4