Question

A lot consists of 144 ball pens of which 20 are defective and others good. Nutri will buy a pen if it is good, but will not buy if it is defective. the shopkeeper draws one pen at random and gives it to her. What is the probability that
(i)She will buy it?
(ii)She will not buy it?

Answer 1

SOLUTION :

Given : Total number of ball pens in a lot = 144

Total number of outcomes = 144

Number of defective ball pens = 20  

Number of good ball pens = 144 - 20 = 124

(i) Let E1 = Event of buying (a good ball pen)

Number of good ball pens = 124

Number of outcome favourable to E1 = 124

Probability (E1) = Number of favourable outcomes / Total number of outcomes

P(E1) = 124/144 = 31/36  

Hence, the required probability She will buy it (a good ball pen) , P(E1) = 31/36 .

(ii) Let E2 = Event of not buying (a defective ball pen)

Number of defective ball pens = 20

Number of outcome favourable to E2 = 20

Probability (E2) = Number of favourable outcomes / Total number of outcomes

P(E2) = 20/144 = 5/36  

Hence, the required probability She will not buy it (a defective ball pen) , P(E2) = 5/36 .

HOPE THIS ANSWER WILL HELP  YOU….

Answer 2

Hey freind your answer is here
Probability= Number of favourable outcomes/
Total number of outcomes
Total number of outcomes = 144
1) Number of favourable outcomes = 124
Probability = 124/144 = 31/36
2) Number of favourable outcomes = 20
Probability = 20/144 = 5/36
Hope it will help you
Please mark my answer as brainliest answer