A lot contains 2% defective items and 40 2 Items chosen from it. Another lot Contains 1% defective items and 60 items chosen from it. Find E(P1-P2)
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P (X = 2) = P (two defective items from the lot) = P(2 defective, 2 non-defective bulbs) = 6 C 4 2 C 2 4 C 2 = 1 5 6 Therefore the required probability distribution is as follows: X : 0 1 2
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