Question

A lot of 1200 kg is lifted using a simple machine having a velocity ratio of 5 find out the efficiency of machine if effort applied 300 kg

Answer 1

A lot of 1200 kg is lifted using a simple machine having a velocity ratio of 5. If effort applied 300 kg, the efficiency of machine is 80%

Step-by-step explanation:

Given

Effort Applied (E) = 300 kg

Load (L) = 1200 kg

We know that

Mechanical Advantage

$MA=\frac{L}{E}$

$\implies MA=\frac{1200}{300}$

$\implies MA=4$

Given,

Velocity ratio (VR) = 5

We know that

Efficiency

$\eta=\frac{MA}{VR}\times 100$

Thus,

Efficiency

$\eta=\frac{4}{5}\times 100$

$\implies \eta=80\%$

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